lua与luajit string hash算法对比

3.8k 词

说明

研究lua与luajit两种string hash算法的原理,以及性能对比

string hash

lua

  1. 如果string长度小于32,则会对所有字符串的字符进行遍历,然后计算hash值
  2. 如果string长度大于等于32,则把string进行等分,等分间隔为长度/32+1,然后取每等分的第一个字符进行hash值计算。所以不管字符串多长,最多会循环32次

代码

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unsigned int (const char *str, size_t l, unsigned int seed) {
unsigned int h = seed ^ cast(unsigned int, l);
size_t l1;
size_t step = (l >> LUAI_HASHLIMIT) + 1; // LUAI_HASHLIMIT值为5,l是字符串长度,不是一
for (l1 = l; l1 >= step; l1 -= step)
h = h ^ ((h<<5) + (h>>2) + cast_byte(str[l1 - 1]));
return h;
}

luajit

  1. 如果string小于4,则会取字符串的第一位,最后一位,以及中间位,进行hash值计算
  2. 如果string长度大于等于4,则会取字符串第1~4位,最后4位,len/2-2~len/2+2,len/4-1~len/4+3,进行hash计算

代码

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// 代码我整理了封装了下,用来展示和测试

#define lj_rol(x, n) (((x)<<(n)) | ((x)>>(-(int)(n)&(8*sizeof(x)-1))))

int luajit_hash(const char *str, size_t len)
{
unsigned int a, b, h = len;
if (len >= 4) { /* Caveat: unaligned access! */
a = lj_getu32(str);
h ^= lj_getu32(str + len - 4);
b = lj_getu32(str + (len >> 1) - 2);
h ^= b; h -= lj_rol(b, 14);
b += lj_getu32(str + (len >> 2) - 1);
}
else if (len > 0) {
a = *(const unsigned char *)str;
h ^= *(const unsigned char *)(str + len - 1);
b = *(const unsigned char *)(str + (len >> 1));
h ^= b; h -= lj_rol(b, 14);
}
a ^= h; a -= lj_rol(h, 11);
b ^= a; b -= lj_rol(a, 25);
h ^= b; h -= lj_rol(b, 16);
return h;
}

分析

从采样随机性及次数上来看,肯定是lua原生自带的hash算法好。但也因为采样次数增加,导致原生hash算法的性能会有损失

性能对比

对lua以及luajit的string hash算法,进行不同字符串长度的性能对比

测试环境

操作系统:Debian GNU/Linux 8
CPU:Intel(R) Xeon(R) CPU E5-2640 v2 @ 2.00GHz
内存:64G

测试代码

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#include <string>
#include <time.h>
#include <stdlib.h>
#include <stdio.h>

static const int lua_hash_seed = 0;

int lua_hash(const char *str, size_t len)
{
unsigned int h = lua_hash_seed ^ (unsigned int)len;
size_t step = (len >> 5) + 1;
for (; len >= step; len -= step)
h ^= ((h << 5) + (h >> 2) + (unsigned char)(str[len - 1]));
return h;
}


#define lj_rol(x, n) (((x)<<(n)) | ((x)>>(-(int)(n)&(8*sizeof(x)-1))))

int luajit_hash(const char *str, size_t len)
{
unsigned int a, b, h = len;
if (len >= 4) { /* Caveat: unaligned access! */
a = lj_getu32(str);
h ^= lj_getu32(str + len - 4);
b = lj_getu32(str + (len >> 1) - 2);
h ^= b; h -= lj_rol(b, 14);
b += lj_getu32(str + (len >> 2) - 1);
}
else if (len > 0) {
a = *(const unsigned char *)str;
h ^= *(const unsigned char *)(str + len - 1);
b = *(const unsigned char *)(str + (len >> 1));
h ^= b; h -= lj_rol(b, 14);
}
a ^= h; a -= lj_rol(h, 11);
b ^= a; b -= lj_rol(a, 25);
h ^= b; h -= lj_rol(b, 16);
return h;
}

void random_string(std::string &str, size_t size)
{
for (int i = 0; i < size; ++i)
{
str.push_back((char)(rand() % 255));
}
}

#define HASH_COUNT 100000
int a[HASH_COUNT];
int main()
{
std::string str;

srand(clock());

int step = 1;
for (int len = 1; len <= 65535; len += step)
{
printf("string len = %d:n", len);

random_string(str, step);

{
clock_t start = clock();
for (int i = 0; i < HASH_COUNT; ++i)
{
a[i] = luajit_hash(str.c_str(), str.size()); // 防止编译器优化;
}
clock_t use_time = clock() - start;

printf("tluajit use: %lfn", use_time*1.0 / CLOCKS_PER_SEC);
}

{
clock_t start = clock();
for (int i = 0; i < HASH_COUNT; ++i)
{
a[i] = lua_hash(str.c_str(), str.size());
}
clock_t use_time = clock() - start;

printf("tlua use: %lfn", use_time*1.0 / CLOCKS_PER_SEC);
}
}

return 0;
}

测试结果

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string len = 1:
luajit use: 0.000615
lua use: 0.000205
string len = 2:
luajit use: 0.000410
lua use: 0.000352
string len = 3:
luajit use: 0.000426
lua use: 0.000505
string len = 4:
luajit use: 0.000485
lua use: 0.000552
string len = 5:
luajit use: 0.000531
lua use: 0.000803
string len = 6:
luajit use: 0.000455
lua use: 0.000910
string len = 7:
luajit use: 0.000479
lua use: 0.001106
...
string len = 31:
luajit use: 0.000483
lua use: 0.005269
string len = 32:
luajit use: 0.000506
lua use: 0.002439
...
  • 可以看到,除了1,2长度的字符串,lua原生hash快,其他都是luajit快。
    漫的速度大致可以通过lua原生hash的循环次数大致估算,如果循环满32次,则性能大致是luajit的1/10倍,如果为16次则为1/5。

结论

  1. lua原生的hash算法会导致性能的开销,测试最慢为0.005s/10W次,而luajit为0.0004s/10W次
  2. 性能开销带来的同时,从算法层面看到,lua原生的hash算法会跟好,不过这还得需要在实际使用当中进行测试才能得到更准确得结论